can anyone please solve this question
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We have lots of things to prove we'll gonna solve them one by one ::-
In an adjoining figure ∆ ABC ;
1. AB = AC
Since, Angle ADB = Angle ADC [Each 90°]
Therefore, we can draw the conclusion that opposite sides of equal angles are equal.
2. Angle ADB = Angle ACB
[Each 90° or AD ⍊ BC such that ABC is a complete triangle]
3. AD = AD
We know that AB = AC so, opposite angles of equal sides are also equal thus, in ∆ ABC ,, Angle ACB = Angle ABC and thus, AD = AD (O.S.O.E.A) or use the above reason.
4. ∆ ABD ≊ ∆ ACD [By SAS criteria]
- AB = AC [S]
- Angle ABD = Angle ACD [A]
- AD = AD [S]
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