Math, asked by laharipragna, 1 year ago

can anyone pls answer this question

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Answered by abhi178
1
x^( logy - logz ) .y^( logz - logx ) .z^(logx - logy) = P ( let)


take both sides log

according to log mn = log m + log n &
log mⁿ = n log m rule ,

( logy - logz ).logx + ( logz - logx ).logy + ( log x - logy ).logz = logP

logy.logx - logz. logx + logz.logy - logx.logy + logx.logz - logy.logz = logP

0 = logP

P = e^0 = 1 ( answer )

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