can anyone pls answer this question
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x^( logy - logz ) .y^( logz - logx ) .z^(logx - logy) = P ( let)
take both sides log
according to log mn = log m + log n &
log mⁿ = n log m rule ,
( logy - logz ).logx + ( logz - logx ).logy + ( log x - logy ).logz = logP
logy.logx - logz. logx + logz.logy - logx.logy + logx.logz - logy.logz = logP
0 = logP
P = e^0 = 1 ( answer )
take both sides log
according to log mn = log m + log n &
log mⁿ = n log m rule ,
( logy - logz ).logx + ( logz - logx ).logy + ( log x - logy ).logz = logP
logy.logx - logz. logx + logz.logy - logx.logy + logx.logz - logy.logz = logP
0 = logP
P = e^0 = 1 ( answer )
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