Question

Can anyone pls solve a^9-b^9.pls

Answer 1

${\large{\mathfrak{\underline{\underline{Solution :}}}}}$

$\sf{a^9 - b^9}$

$\sf{We \ can \ also \ write \ this \ as \ -}$

$\sf{(a^3)^3 - (b^3)^3}$

${\boxed{\sf{x^3 - y^3 \ = \ (x - y)(x^2 + y^2 + xy)}}}$

$\sf{Here, \ x \ = \ a^3 \ \ and \ \ y \ = \ b^3}$

$\sf{= \ (a^3 - b^3)[ \ (a^3)^2 + (b^3)^2 + a^3b^3 \ ]}$

$\sf{= \ (a^3 - b^3)(a^6 + b^6 + a^3b^3)}$

$\sf{'Gain \ applying \ the \ identity \ in \ (a^3 - b^3).}$

$\sf{Now, \ x \ = \ a \ \ and \ \ y \ = \ b}$

$\sf{= \ [ \ (a - b)(a^2 + b^2 + ab) \ ] (a^6 + b^6 + a^3b^3)}$

$\sf{= \ (a - b)(a^2 + b^2 + ab)(a^6 + b^6 + a^3b^3)}$

Answer 2

Hi thanks for points

Hope it helps you