can anyone plss explain this question
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x² - 8x +15 = x²-5x-3x-15 = x(x-3) - 5(x-3) = (x-5)(x-3)
2x²-11x+5 = 2x²-10x-x+5 = 2x(x-5) - 1(x-5) = (2x-1)(x-5)
2x² - 7x+3 = 2x²-6x-x+3 = 2x(x-3) - 1(x-3) = (2x-1)(x-3)
So, (x² - 8x +15)(2x²-11x+5)(2x² - 7x+3) = (x-5)²(x-3)²(2x-1)²
So, its square root is (x-5)(x-3)(2x-1)
2x²-11x+5 = 2x²-10x-x+5 = 2x(x-5) - 1(x-5) = (2x-1)(x-5)
2x² - 7x+3 = 2x²-6x-x+3 = 2x(x-3) - 1(x-3) = (2x-1)(x-3)
So, (x² - 8x +15)(2x²-11x+5)(2x² - 7x+3) = (x-5)²(x-3)²(2x-1)²
So, its square root is (x-5)(x-3)(2x-1)
Anonymous:
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ok sir, sure
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refer the pic
hope it'll help
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hope it'll help
mark it as brainliest
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