Can anyone plz solve this question of linear equations in two variables ques no.12
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Hey. !!
your answer is ---
2x-3y+6 =0 or 2x-3y = -6 ...(1)
2x+3y-18 =0 or 2x+3y =18 ...(2)
adding equation (1)&(2), we get
2x-3y+2x+2y = -6+18
=> 4x = 12
=> x = 12/4
=> x = 3
put this value in equation (1), we get
2×3 - 3y = -6
=> 6 - 3y = -6
=> 3y = 12
=> y = 12/3
=> y = 4
===============
hope it help you
===============
your answer is ---
2x-3y+6 =0 or 2x-3y = -6 ...(1)
2x+3y-18 =0 or 2x+3y =18 ...(2)
adding equation (1)&(2), we get
2x-3y+2x+2y = -6+18
=> 4x = 12
=> x = 12/4
=> x = 3
put this value in equation (1), we get
2×3 - 3y = -6
=> 6 - 3y = -6
=> 3y = 12
=> y = 12/3
=> y = 4
===============
hope it help you
===============
priyanshim31:
Thank you so much but I needed it by another method-elimination by substitution
ye whi method hai
its elimination by equation coefficients
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