can anyone plzz explain me how the II is correct or how to check thst the point lies inside a circle
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since <DEA=90degree so,<DEC=90degree.(180-90)due to linearpair.
in quadrilateral <DBC+<DEC=90+90=180degree.
As the sum of opposite angles of d Quadrilateral is 180degree,so its a cyclice quardrilateral , HENCE , B,C,E,D are concyclic i.e lie on circle
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