Question

Can anyone prove it
(3P/7 + 7/6P)² - (3P/7 - 7/6P) = 2

Please solve it fast and best answer will be marked as a brainlist.

Answer 1

$<b><marquee>Heya</marquee>$

There is a correction in the question.

The correct question is :-

(3P/7 + 7/6P)^2 - (3P/7 - 7/6P)^2 = 2

Prove it.


Solution :-

Using identity,

a^2 - b^2 = (a - b)(a + b)

Here a = (3P/7 + 7/6P) and
b = (3P/7 - 7/6P)

Now, according to the formula,

= (a - b)(a + b)

= [(3P/7 + 7/6P) - (3P/7 - 7/6P)] [(3P/7 + 7/6P) + (3P/7 - 7/6P)]

Opening the brackets,

= (3P/7 + 7/6P - 3P/7 + 7/6P)(3P/7 + 7/6P + 3P/7 - 7/6P)

= (7/6P + 7/6P)(3P/7 + 3P/7)

= (14/6P)(6P/7)

= 2

Hence proved.

$<b><marquee>Hope this helps you.</marquee>$