Question

can anyone slove this​

Answer 1

Answer:

I don't know this question

Answer 2

Answer:

Option A

3 R / 4

Explanation:

★ WE know that ;

» Current always flows in the wire with least resistance or no resistance ( in this case ) .

» So ; Remove the resistance near to A and B

U will see only square will be remaining !

on solving square

3R in series and 1 R in parallel

we get

3R × R / 3R + R = 3 R² / 4R

Net resistance be 3R / 4 .