Math, asked by rubby28, 1 year ago

can anyone solve it pls.

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Answers

Answered by Keepmoving
1
Here is ur answer frnd!! Check it out !!
If it helped u Mark Brainliest
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rubby28: hi dear how to mark brainliest??
Keepmoving: Mmm.. There is a button MAYBE written brainliest
rubby28: ok I will check.
Answered by boffeemadrid
0

Answer:


Step-by-step explanation:

The given equation is:

(\frac{x^{a}}{x^{b}})^{a+b}{\times}(\frac{x^{b}}{x^{c}})^{b+c}{\times}(\frac{x^{c}}{x^{a}})^{c+a}

=(x^{a-b})^{a+b}{\times}(x^{b-c})^{b+c}{\times}(x^{c-a})^{c+a}

=x^{a^{2}-b^{2}} {\times}x^{b^{2}-c^{2}}{\times}x^{c^{2}-a^{2}}

=x^{0}

=1

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