can anyone solve my question no 23
Answers
First we find the proportion of mass of calcium and oxygen in calcium oxide.
In CaO, Ca:O=5:2
In other word,
40. 00g calcium reacts with oxygen =16.00g
5.00g carbon will react with oxygen = 2.00g
Ca + O------->CaO
40g 16g 40+16=56g
5g 8g 5+8 =7g
Therefore, 5.00g of calcium will always react with 2.00g of oxygen to form 7g of calcium oxide, even if larger amount (20.00g) of oxygen is present. This means when 5.00g of calcium is burnt in 20.00 g of oxygen, only 2.00g of oxygen will be used to produce 7.00 g of calcium oxide. The remaining 18.00 g of oxygen will remain as it is. This reaction will be governed by the law of constant proportion.
Hope u got your answer
By - - - Harsh. P