Question

can anyone solve the answer . plz say me as fast as possible​

Answer 1

I hope this is the answer! Try doing by yourself once with the formula given in the attachment!

Answer 2

★ Given -:

Mohit invests (Principal) = ₹7290

Rate (R) = 13 1/9 %

Time (T) = 3 years

★ To find -:

The compound interest

★ Solution -:

We know that ,

$A (Amount) = P \left(1 + \dfrac{R}{100}\right)^{T}$

by putting the values

( R = 13 1/9 % = 118/9 % )

$A = 7290 \times \left(1 + \dfrac{\frac{118}{9}}{100}\right) ^{3}$

$= 7290 \times \left(1 + \dfrac{118}{900}\right)^{3}$

$= 7290 \times \left(\dfrac{1018}{900}\right)^{3}$

$= 7290 \times \dfrac{1018}{\cancel{90}0} \times \dfrac{1018}{\cancel{9}00} \times \dfrac{1018}{\cancel{9}00}$

$= \dfrac{1018 \times 1018 \times 1018}{10 \times 100 \times 100 }$

$= 1.018 \times 10.18 \times 1018$

$\purple{Amount = 10,550\: (approx)}$

We know that ,

Amount = CI + Principal

Or

CI = Amount - Principal

___________________________________

by putting the values

10550 - 7290

= ₹ 3260

$\purple{CI = 3260 \: rupees}$