can anyone solve the following linear equation by only cross-multiplication method...
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2
Answer:
225J
Given, velocityofobject,v=5ms
−1
;
kineticenergyofanobject,E
K
=25J
E
K
=
2
1
mv
2
or 25=
2
1
×m×(5)
2
or m=
25
50
=2kg
When the velocity triples,
E
K
=
2
1
mv
2
=
2
1
×2×(15)
2
=225J
Answered by
1
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