if log¹⁰x=a+b and y=10 power a-b then find the value of log¹⁰(x²y³) in terms of a-b? pls ans the question I want immediately?
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log¹⁰x=a+b and y=10 power a-b then find the value of log¹⁰(x²y³) in terms of a-b? pls ans the question I want
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Step-by-step explanation:
Given :-
log¹⁰x=a+b and y=10 power a-b
To find :-
Find the value of log¹⁰(x²y³) in terms of a-b ?
Solution :-
Given that
log¹⁰x=a+b-------(1)
y=10^(a-b)
=> log ¹⁰ y = a -b -----(2)
Now,
log ¹⁰ (x²y³)
We know that
log ab = log a + log b
=> log ¹⁰ x² + log ¹⁰ y³
We know that
log a^m = m log a
=>2 log ¹⁰x + 3 log¹⁰ y
=> 2 (a+b)+3(a-b)
=> 2a+2b +3a-3b
=> (2a+3a)+(2b-3b)
=> 5a -b
Answer:-
The value of log¹⁰ (x²y³) is 5a -b
Used formulae:-
→ log ab = log a + log b
→ log a^m = m log a
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