can anyone solve these questions. (ll)(b) and (lll)(a)
Attachments:
Answers
Answered by
1
2b)...√(x²+1).
[ we know that d(√x)/dx= 1/2√x]
differentiating with respect to x
we get
2x/2√(x²+1)
=x/√(x²+1)
3a). √(ax²+2bx+c)
differentiating with respect to x we get,
2ax+2b/2(√ax²+2bx+c)
=ax+b/(√ax²+2bx+c)
I hope this will help u :)
[ we know that d(√x)/dx= 1/2√x]
differentiating with respect to x
we get
2x/2√(x²+1)
=x/√(x²+1)
3a). √(ax²+2bx+c)
differentiating with respect to x we get,
2ax+2b/2(√ax²+2bx+c)
=ax+b/(√ax²+2bx+c)
I hope this will help u :)
Similar questions