Find the heat given out when 10 g of steam at 100 ºC condenses and cools to water at 50 ºC
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Hey there!
Heat given out when 10g of steam at 100°C converts to water at 50°C.
Step 1:- Heat given out when 10g of steam at 100°C coverts into water at 100°C.
Latent heat of vaporization = 540cal
Q = 540×10 = 5400 cal.
Step 2:- Heat given out when 10g water at 100°C converts to water at 50°C.
Here,
Mass = 10g
∆T change in temperature = 100-50 = 50°C
Formula Q = ms∆T
= 10×1×50 = 500Cal.
Adding up these,
5400cal + 500 cal = 5900 Cal.
Therefore 5900 cal heat is given out when 10g of steam at 100°C converts to water at 50°C.
Hope you got that!. any doubt.. ask me
:)
Heat given out when 10g of steam at 100°C converts to water at 50°C.
Step 1:- Heat given out when 10g of steam at 100°C coverts into water at 100°C.
Latent heat of vaporization = 540cal
Q = 540×10 = 5400 cal.
Step 2:- Heat given out when 10g water at 100°C converts to water at 50°C.
Here,
Mass = 10g
∆T change in temperature = 100-50 = 50°C
Formula Q = ms∆T
= 10×1×50 = 500Cal.
Adding up these,
5400cal + 500 cal = 5900 Cal.
Therefore 5900 cal heat is given out when 10g of steam at 100°C converts to water at 50°C.
Hope you got that!. any doubt.. ask me
:)
lim22222:
can you change all the unit into J
Why?
Cal = how many J???
1 cal = 4.186J
5900cal = 5900×4.186J
thanks
welcome!
Still any doubt?
Some water is stored in a bag of porous material, such as canvas, which is hung where it is exposed to a draught of air. Explain why the temperature of the water is lower than that of the air.
i donno.. post this question.. someone will answer :)
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