can anyone solve this
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It is proved in the explanation section
Step-by-step explanation:
Since AE || BC and DAB is the transversal
\angle DAE=\angle ABC=\angle B∠DAE=∠ABC=∠B
Since AE || BC and AC is the transversal
\angle CAE=\angle ABC=\angle C∠CAE=∠ABC=∠C
But AE bisects \angle CAE∠CAE
\begin{gathered}\angle DAE=\angle CAE\\ \\ \angle B=\angle C\end{gathered}
∠DAE=∠CAE
∠B=∠C
AB = AC [Sides opposite to equal angles are equal]
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