can anyone solve this
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81^sin^2x+81^cos^2x=30,,,
[(81^sin^2x)^2+81]/81^sin^2x=30
let,,,81^sin^2x=Y
y^2+81=30y
sinx=1/2
x=30°. and>>>x=60°
[(81^sin^2x)^2+81]/81^sin^2x=30
let,,,81^sin^2x=Y
y^2+81=30y
sinx=1/2
x=30°. and>>>x=60°
Answered by
0
81^sin^2x+81^cos^2x=30
let, 81^sin^2x
y^2+81=30y
sinx =1/2
x=30°,x=60°
let, 81^sin^2x
y^2+81=30y
sinx =1/2
x=30°,x=60°
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