Math, asked by Sandeep03edu, 1 year ago

can anyone solve this

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Answers

Answered by ajeshrai
0
81^sin^2x+81^cos^2x=30,,,

[(81^sin^2x)^2+81]/81^sin^2x=30

let,,,81^sin^2x=Y

y^2+81=30y

sinx=1/2

x=30°. and>>>x=60°
Answered by sruthilakadi
0
81^sin^2x+81^cos^2x=30
let, 81^sin^2x
y^2+81=30y
sinx =1/2
x=30°,x=60°
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