can anyone solve this linear eqn by substitution method
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sry for the bad handwritting
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omkar200227:
y = b....?
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Given Equation is x + y = a - b ----- (1)
Given Equation is ax - by = a^2 + b^2 ----- (2)
Equation (1) can be written as:
= > x = a - b - y ------ (3)
Substitute (3) in (2), we get
= > ax - by = a^2 + b^2
= > a(a - b - y) - by = a^2 + b^2
= > a^2 - ab - ay - by = a^2 + b^2
= > -ab - by = b^2 + ab
= > -(a + b)y = b(a + b)
= > -y = b(a + b)/(a + b)
= > -y = b
= > y = -b
Substitute y = -b in (1), we get
= > x + y = a - b
= > x - b = a - b
= > x = a - b + b
= > x = a.
Therefore the value of x = a and y = -b.
Hope this helps!
Given Equation is ax - by = a^2 + b^2 ----- (2)
Equation (1) can be written as:
= > x = a - b - y ------ (3)
Substitute (3) in (2), we get
= > ax - by = a^2 + b^2
= > a(a - b - y) - by = a^2 + b^2
= > a^2 - ab - ay - by = a^2 + b^2
= > -ab - by = b^2 + ab
= > -(a + b)y = b(a + b)
= > -y = b(a + b)/(a + b)
= > -y = b
= > y = -b
Substitute y = -b in (1), we get
= > x + y = a - b
= > x - b = a - b
= > x = a - b + b
= > x = a.
Therefore the value of x = a and y = -b.
Hope this helps!
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