Question

can anyone solve this one​

Answer 1

Answer:

(x^a/x^b)^(a^2-ab+b^2)×(x^b/x^c)^(b^2+bc+c^2)×

(x^c/x^a)^(c^2+ca+a^2)

=(x)^(a-b)(a^2+ab+b^2)×(x)^(b-c)(b^2+bc+c^2)×

(x)^(c-a)(c^2+ca+a^2)

=x^(a^3-b^3).x^(b^3-c^3).x^(c^3-a^3)

=x^(a^3-b^3+b^3-c^3+c^3-a^3)

=x^0

=1