Math, asked by Chimmin, 3 months ago

can anyone solve this plsss (don't spam) ​

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Answers

Answered by aarushtendulkar
1

Answer:

hope this helps

Step-by-step explanation:

let us make the denominators equal

so it is

(sin a + cos a)²/(sin a - cos a)(sin a + cos a) + (cos a - sin a)²/(sin a - cos a)(sin a + cos a)

= (sin a + cos a)² + (cos a - sin a)² / sin²a - cos²a

= sin²a + 2 sin a cos a + cos²a + cos²a - 2 sin a cos a + sin²a / sin²a - cos²a

2 sin a cos a will get cancel

= 2sin²a + 2cos²a / sin²a - cos²a

= 2( sin²a + cos²a ) / sin²a - ( 1 - sin²a)

= 2 ( 1 ) / sin²a - 1 + sin² a

= 2 / 2sin²a - 1

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