Question

can anyone solve this problem​

Answer 1

Answer:

let us assume 2+√3 as rational.

let us assume 2+√3 as rational.⇒2+√3=a/b

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b∵a and b are positive integers 

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b∵a and b are positive integers ∴a-2b/b is rational

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b∵a and b are positive integers ∴a-2b/b is rational⇒√3 is rational

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b∵a and b are positive integers ∴a-2b/b is rational⇒√3 is rationalbut we know that √3 is irrational 

let us assume 2+√3 as rational.⇒2+√3=a/b∴2-a/b=-√3 or √3=a/b-2⇒√3=a/b-2√3=a-2b/b∵a and b are positive integers ∴a-2b/b is rational⇒√3 is rationalbut we know that √3 is irrational ∴⇒2+√3 is irrational

here is the correct answer please mark me brainliest and give thanks