can anyone solve this problem
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by using identity a³+b³=(a+b) (a²-ab+b²)
=(cos 15+sin15) (cos²15-cos15.sin15+sin²15)/cos15+sin15
=1-cos15.sin15
=(cos 15+sin15) (cos²15-cos15.sin15+sin²15)/cos15+sin15
=1-cos15.sin15
dhananjaysharma2:
please solve more
what is the answer
1-1/2(2cos15sin15) =1-1/2(sin(15+15)-sin(15-15)=1-1/2(sin30)=1-1/4=3/4
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I think this is the answer
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please solve it fully
There is no way to proceed further
i solve it
that's the final answer
What is the answer then??
no baby it is not final answer
is the answer given
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