Math, asked by MrSoyal, 25 days ago

can anyone solve this question
plz anyone solve urgent. ​

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Answers

Answered by shreyappradhan4
1

Step-by-step explanation:

a. In ∆ABC

angle A +angle B +angle C = 180°(angle sum property)

5x+3x+2x= 180°

10x=180°

x=180°/10

x=18°

angle A= 90°

angle B= 54°

angle C= 36°

b. In∆PQR

angle P+angle Q+angle R= 180°

x+x+x= 180°

3x= 180°

x= 180°/3

x= 60°

angle P=R=Q=60°

c. In∆NLM

angle N+angle L+angle M= 180°

x-10°+30°+x+10°=180°

2x+30°=180°

2x=150°

x=75°

N=65

M= 85

d. Angle P+Q+R= 180°

90°+ 2x+ 3x= 180°

5x= 180°-90°

x= 18°

Q=36

R=54

Answered by kadeejasana2543
1

Answer:

(a)the angles ∠A=90°,∠B=54°,∠C=36°

(b) ∠P=Q=R=60°

(c) ∠L=30°,∠M=85°,∠N=65°

(d)∠P=90°,∠Q=36°,∠R=54°

Step-by-step explanation:

Total of all angles in a triangle is 180°,.  so  

(a)

       5x+3x+2x=180\\\\10x=180\\\\x=18, thus the angles

       5x=5(18)=90,\\\\\ 3x=3(18)=54,\\\\\ 2x=2(18)=36 degrees respectively.

(b)

       x+x+x=3x=180\\\\x=60

       thus each angle is 60°.

(c)

       30+x+10+x-10=180\\\\2x=150\\\\x=75

       thus the angles are 30°,85°,65°.

(d)

       2x+3x+90=180\\\\5x=90\\\\x=18

       hence each angle is 90°,36°,54°

Hence the answers

thank you

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