Question

Can anyone solve this question?
Q no.3

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Answer 1

Answer:

2

Step-by-step explanation:

Given: sin⁴α + cos⁴β + 2 = 4sinαcosβ

⇒ (sin⁴α) + (cos⁴β)  + 1 + 1 - 4sinαcosβ = 0

⇒ sin⁴α + cos⁴β - 2sin²α + 2sin²α + 2cos²β - 2cos²β + 1 + 1 - 4sinαcosβ = 0

⇒ (sin⁴α + 1 - 2sin²α) + (cos⁴β + 1 - 2cos²β) + 2sin²α + 2cos²β - 4sinαcosβ = 0

⇒ (sin²α - 1)² + (cos²β - 1)² + 2(sinα - cosβ)² = 0

⇒ sin²α = 1, cos²β = 1, sinα = cosβ

⇒ sinα = 1, cosβ = 1

Now.

sinα + cosβ

= 1 + 1

= 2

Hope it helps!

Answer 2

Answer:

Hello mate

Your answer is 2.....