Question

can anyone solve this question with statement​

Answer 1

Answer :

Option (1) : (-5)

Solution :

• Given : (x-1)(x³+x²-2x) = x⁴+ax³+bx²+cx

• To find : a + b - c = ?

We have ,

=> (x - 1)(x³ + x² - 2x) = x⁴ + ax³ + bx² + cx

=> x⁴ + x³ - 2x² - x³ - x² + 2x = x⁴ + ax³ + bx² + cx

=> x⁴ - 3x² + 2x = x⁴ + ax³ + bx² + cx

=> x⁴ + 0x³ + (-3)x² + 2x = x⁴ + ax³ + bx² + cx

Now ,

Comparing the coefficients of x³ , x² , x both the sides , we get ;

a = 0

b = -3

c = 2

Now ,

=> a + b - c = 0 + (-3) - 2

=> a + b - c = -3 - 2

=> a + b - c = -5

Hence ,

a + b - c = -5

Answer 2

Answer:

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Step-by-step explanation:

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