Question

can anyone solve this
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Answer 1

Given pth term = 1/q 

That is ap

 = a + (p - 1)d

= 1/q aq + (pq - q)d = 1  --- (1) 

Similarly, we get ap + (pq - p)d = 1  --- (2)


 From (1) and (2),

we get

 aq + (pq - q)d = ap + (pq - p)d  aq - ap = d[pq - p - pq + q] a(q - p) = d(q - p)

Therefore, a = d

 Equation (1) becomes, 


dq + pqd - dq = 1   d = 1/pq

 Hence a = 1/pq

Consider, Spq = (pq/2)[2a + (pq - 1)d]                     = (pq/2)[2(1/pq) + (pq - 1)(1/pq)]                     = (1/2)[2 + pq - 1]                     = (1/2)[pq + 1]

Answer 2

here is your answer

hope it helps you....