Question

can anyone tell me answer of this question

Answer 1

given,

force*displacement = $\sqrt{3}$

F*d cosФ=$\sqrt{3}/2$

cosФ=$\sqrt{3}/(2*F*d)$

cosФ=1/2

cosФ = cos60

Ф = 60 degree

so Ф/2 = 30 degree

so work done at Ф/2 is

w = F*d*cosФ/2

w = $\sqrt{3}*\sqrt{3}/2$

w= 3/2 joule

Answer 2

Answer:

trigonometry

Explanation: