Question

can anyone tell me how to solve this Equation​

Answer 1

Step-by-step explanation:

Let 3x+4y34+3x−2y15=5     ...(1)

and 3x−2y25−3x+4y8.5=4.5     ...(2)

Multiplying eq(2) with 4 we get, 

3x−2y100−3x+4y34=18    ...(3)

Adding eq(1) and eq(3) we get, 

3x−2y115=23=>3x−2y=5       ...(4)

Substituting 3x−2y=5 in the eq(1), we get,

3x+4y34+515=5=>3x+4y34=2

=>3x+4y=17                   ...(5)

Subtracting eq(4) from eq(5) we get, 

6y=12=>y=2

Substituting y=2 in the eq(5) we get,

3x+4(2)=17=>x=3