Question

can anyone who solve this maths question??​

Answer 1

θ = 60°,0°

Step-by-step explanation:

Given Equation is (cos²θ - 3cosθ + 2)/sin²θ = 1

⇒ cos²θ - 3cosθ + 2 = sin²θ

⇒ cos²θ - 3cosθ + 2 = (1 - cos²θ)

⇒ cos²θ - 3cosθ + 2 - 1 + cos²θ = 0

⇒ 2cos²θ - 3cosθ + 1 = 0

⇒ 2cos²θ - 2cosθ - cosθ + 1 = 0

⇒ 2cosθ(cosθ - 1) - (cosθ - 1) = 0

⇒ (2cosθ - 1)(cosθ - 1) = 0

⇒ cosθ = (1/2) (or) cosθ = 1

⇒ θ = 60° (or) 0°

Answer 2

Step-by-step explanation:

I HOPE THIS ANSWER IS HELPFUL FOR YOU,........

THANKS