can everyone answer the question about algebraic expression: if x = 2a² + 3b²- 5 ab y= b²- 3a²+ 7ab and z= 6a² -b²+ab,find :- 1) x-y+z
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1
Answer:
(i) x + y + z = 4a2 + b2 – 6ab + 3b2 – 2a2 + 8ab + 6a2 + 8b2 – 6ab
= 4a2 – 2a2 + 6a2 + b2 + 3b2 + 8b2 – 6ab + 8ab – 6ab
= 10a2 – 2a2 + 12b2 – 12ab + 8ab
= 8a2 + 12b2 – 4ab
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Answered by
0
Answer:
−7a2+3b2+3ab
hope it helps
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