Can I asked how to compute a polygon with 27 diagonals using this formula given by our professor
d=n/2(n-3)
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Hey mate,
Just plug in the value,
27×2 = n^2 - 3n
n^2 - 3n - 54 = 0
n^2 - 9n + 6n - 54 = 0
n(n-9) +6 (n-9) = 0
n = -6 or 9
can't be negative so = 9
hope this helps you out!
Just plug in the value,
27×2 = n^2 - 3n
n^2 - 3n - 54 = 0
n^2 - 9n + 6n - 54 = 0
n(n-9) +6 (n-9) = 0
n = -6 or 9
can't be negative so = 9
hope this helps you out!
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