Question

Can i Get the answer of my question​

Answer 1

Answer:

Hope this helps.

$\displaystyle\sec\theta+\tan\theta=m\\\\\Rightarrow1+\sin\theta=m\cos\theta\\\\\Rightarrow(1+\sin\theta)^2=m^2\cos^2\theta\\\\\Rightarrow(1+\sin\theta)^2=m^2(1-\sin^2\theta)\\\\\Rightarrow(1+\sin\theta)^2=m^2(1-\sin\theta)(1+\sin\theta)\\\\\Rightarrow1+\sin\theta=m^2(1-\sin\theta)\\\\\Rightarrow(m^2+1)\sin\theta=m^2-1\\\\\Rightarrow\sin\theta=\frac{m^2-1}{m^2+1}$