Math, asked by Vrushalikawalkar, 8 months ago

Can solve any don't take points for free. Or don't give useless answers.

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Answered by nigarg82
1

Answer:

1. (n-2)180/n= 150

180n-360= 150n

180n-150n= 360

30n= 360

n= 360/30

n= 12

The polygon has 12 sides.

2. Angle sum property of polygon:

(n-2)180 where ‘n’ is the no. of sides

⇒ (10-2)180

8×180

1440°

3. 360/n= Measure of each exterior angle

360/9

40°

4.

(a) 4x+5x+(3x+20)+(2x+18)= 360

14x+38= 360

14x= 322

x= 23

(b) (3x+11)= (5x-9) [opp angles of parallelogram]

3x-5x= -9-11

-2x= -20

2x= 20

x= 10

(c) 80+(11x-10)= 180 [adjacent angles are supplementary]

70+11x= 180

11x= 110

x= 10

(d) To solve this, we will first find the sum of angles of this polygon.

(6-2)180

4×180

720°

⇒ (3x+10)+175+3x+5x+4x+115= 720

15x+300= 720

15x= 420

x= 28

Hope it helps

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