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1. (n-2)180/n= 150
180n-360= 150n
180n-150n= 360
30n= 360
n= 360/30
n= 12
The polygon has 12 sides.
2. Angle sum property of polygon:
(n-2)180 where ‘n’ is the no. of sides
⇒ (10-2)180
8×180
1440°
3. 360/n= Measure of each exterior angle
360/9
40°
4.
(a) 4x+5x+(3x+20)+(2x+18)= 360
14x+38= 360
14x= 322
x= 23
(b) (3x+11)= (5x-9) [opp angles of parallelogram]
3x-5x= -9-11
-2x= -20
2x= 20
x= 10
(c) 80+(11x-10)= 180 [adjacent angles are supplementary]
70+11x= 180
11x= 110
x= 10
(d) To solve this, we will first find the sum of angles of this polygon.
(6-2)180
4×180
720°
⇒ (3x+10)+175+3x+5x+4x+115= 720
15x+300= 720
15x= 420
x= 28
Hope it helps
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