Math, asked by dragomegaman, 1 year ago

Can some explain me this step

Attachments:

Dhinu: which step ??

Answers

Answered by Tanyao1
1
 \cos(\pi - 2h) \: goes \: to \: the \: 2nd \: quadrant \: \\and \: in \: 2nd \: quadrant.... \: the \: value \: for \: cos \: \alpha \: is \: negative \: \\ so \: we \: took \: negtative \: sign


Hope it helps...

dragomegaman: Thank You! I am hell bent on thinking why cos (a+b) is not applied..
Tanyao1: itsokk
Dhinu: you can even apply that formula . the result will be same .....
Similar questions