Question

Can some one please solve Q7 please it is urgent!
Send me photo of that sum please

Answer 1

let the common ratio=x
then length of 1st cube=3x
and 2nd cube =2x
1) TSA of cube=6(side)^2
ratio=6(3x)^2/6(2x)^2
=9/4=9:4
2) volume of cube=(side)^3
ratio of their volume=(3x)^3/(2x)^3
=27x^3/8x^3=27/8
=27:8

hope you get it.....

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Answer 2

here is your answer
let the length of first cube = 3x
length of other cube = 2x
total surface area of first cube = 6a^2 = 6×3x×3x = 54x^2

total surface area of other cube = 6a^2 =
6×2x×2x = 24 x^2
ratio = 54x^2 : 24x^2
= 9:4

volume of first cube = a^3 = (3x)^3 = 3x×3x×3x = 27x^3
volume of other cube a^3 =( 2x)^3 = 2x×2x×2x = 8x^3
ratio = 27^3 : 8x^3
= 27:8

hope his helps you
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