can some one solve this ( simplify and write in exponential form with positive power)
Attachments:
Answers
Answered by
0
(4/5)^2 * (5)^4 * (2/5)^-2 /(5/2)^-3 =?
now,
>(4/5)^2 * (5)^4 * (2/5)^-2 * (5/2)^3
>(4/5)^2 * (5)^4 * (5/2)^2 * (5/2)^3
>(4/5)^2 * (5)^4 * (5/2)^5
> (4)^2 * (5)^-2 * (5)^4 * (5) ^5 * (2)^-5
> (2)^4 * (5)^-2 * (5)^9 * (2)^-5
> (2)^4 * (5)^-2 * (5)^9 * (2)^-5
> (2)^4 * (2)^-5 * (5)^-2 * (5)^9
> (5)^7 * (2)^-1
so,
(4/5)^2 * (5)^4 * (2/5)^-2 /(5/2)^-3 =(5)^7 * (2)^-1
now,
>(4/5)^2 * (5)^4 * (2/5)^-2 * (5/2)^3
>(4/5)^2 * (5)^4 * (5/2)^2 * (5/2)^3
>(4/5)^2 * (5)^4 * (5/2)^5
> (4)^2 * (5)^-2 * (5)^4 * (5) ^5 * (2)^-5
> (2)^4 * (5)^-2 * (5)^9 * (2)^-5
> (2)^4 * (5)^-2 * (5)^9 * (2)^-5
> (2)^4 * (2)^-5 * (5)^-2 * (5)^9
> (5)^7 * (2)^-1
so,
(4/5)^2 * (5)^4 * (2/5)^-2 /(5/2)^-3 =(5)^7 * (2)^-1
Similar questions