can somebody help me to answer this question ?
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Step-by-step explanation:
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Step-by-step explanation:2πrh=2π(y^2-7y+12)
When 2πr cancels on both sides
Rh=(y^2-7y+12)
R×h=(y^2-3y-4y+12)
=Y(y-3)-4(y-3)
=(Y-3)(y-4)
R×h=(y-3)(y-4)
(Y-3)×h=(y-3)(y-4)[since radius =(y-3)]
H=(y-4)
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