Question

Can somebody please solve question number 11

Answer 1

This is your answer please mark me brainlist

Answer 2

Step-by-step explanation:

Draw a line BC parallel to AD

Draw a perpendicular line BE on DF

ABCD is a parallelogram.

BC=AD=25 cm

CD=AB=60 cm

CF=77-CD=17 cm

For Δ BCF

Perimeter of triangle =

$\frac{25 + 26 + 17}{2} = \frac{68}{2} = 34 \: cm$

By using Heron's formula

$\sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{34(34 - 25)(34 - 26)(34 - 17)} \\ = 204 \: {cm}^{2}$

Now, area of ΔBCF =

$\frac{1}{2} \times base \times height$

= 204=1/2×BE×CF

= 408= 17× BE

= 408/17= BE

= 24 cm= BE

Therefore, the height of the trapezium is 24 cm

Hope you have got it

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