Question

Can somebody solve (3^5 x 5^2 x t^4) divided by (6^3 x 125

Answer 1

$\huge{ \underline{ \mathfrak{ \green{ \: Answer}}}}$

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$\displaystyle{\frac{3^5 × 5^2 × t^4}{6^3 ×125}}$

$\displaystyle{\frac{3^5 × 5^2 × t^4}{ {(2×3)}^{3} × 5^3}}$

$\displaystyle{\frac{3^5 × 5^2 × t^4}{2^3 × 3^3 × 5^3}}$

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When the bases are same , and they have different expotential power in dividing form, then the powers are subtracted . So :

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$\displaystyle{\frac{ {3}^{5-3} × {5}^{2-3} × t^4 }{2^3}}$

$\displaystyle{\frac{3^2 × {5}^{-1} × t^4}{8}}$

$\displaystyle{\frac{9 × t^4}{8 × 5}}$

$\displaystyle{\frac{9t^4}{40}}$

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