can someone answer the first question.
I really need to know it fast.
Plssss guys help me.
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Answer:
Step-by-step explanation:
Put the value of n as any number and then apply the pythagoras formula..
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Hey mate.
Let, n=3
then, by the first formula
(n^2-1/2) = 9-1/2 = 8/2 = 4
now using another formula.
(n^2+1/2) = 9+1/2 = 10/2 = 5
Now we've got values
(3,4,5)
So, now check if this a Pythagorean Triplet.
Now, you can take another example by taking n=any odd no.
Hope it helps you.
:-)
Let, n=3
then, by the first formula
(n^2-1/2) = 9-1/2 = 8/2 = 4
now using another formula.
(n^2+1/2) = 9+1/2 = 10/2 = 5
Now we've got values
(3,4,5)
So, now check if this a Pythagorean Triplet.
Now, you can take another example by taking n=any odd no.
Hope it helps you.
:-)
BacchuBHAU:
thanks pal
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