can someone answer this fast
find the angle
how is it congrurent
and how is it a square
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In ΔABC & ΔFBE
∠B=∠B (COMMON)
∠A=∠F=90°
BA=BE (ASA)
∴ΔABC≅ΔFBE
∴∠ABC=∠FBE (CPCT)
To prove ABFG is a square, we have to prove that ABFG is a parallelogram, AB = BF = FG = AG, and one of its interior angles is 90°. are equal to each other only when the two lines are parallel. ... One of the interior angles of quadrilateral ABFG is a right angle.
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