Question

CAN SOMEONE EXPLAIN ME THIS QUESTION? PLEASE.
A tangent PQ at a point P of a circle of
radius 5 cm meets a line through the centre
O at a point Q so that OQ = 13 cm. Find the
length of PQ.​

Answer 1

Answer:

Pls mark as the brainliest....

√(13²-5²)=√169-25=√144= 12 cm

Answer 2

Tangent drawn at a point will be perpendicular to the radius drawn at that point.

So, the triangle OPQ will be a perpendicular triangle with hypotenuse 13 cm and one side 5 cm.

So the third side = PQ = √(13² - 5²) = √(169 - 25) = √144 = 12 cm

PQ = 12 cm