Question

can someone help me answer this??

If the numerator of a fraction is increased by 2
and denominator is decreased by 1, it
becomes 2/3. If the numerator is increased by 1
and denominator is increased by 2 it becomes 1/3
Find the fraction​

Answer 1

Answer:

The numerator and denominator of the fraction is

Step-by-step explanation:

Let the numerator be=x

And the denominator be=x

According to the question, first Condition

Numerator is increased by 2 and denominator is decreased by 1 fraction is 2/3

x+2/x-1=2/3

second condition,

The numerator is increased by 1 and denominator is increased by 2 then fraction becomes 1/3

First Condition

x+2/x-1=2/3

3[x+2]=2[x-1]

3x+6=2x-2

3x-2x=-2-6

x=-8

Second Condition

x+2/x+1=1/3

3[x+2]=x+1

3x+6=x+1

3x-x=6-1

2x=5

x=5/2

Find nerror and denominator by substituting in them

Answer 2

Answer:

Let the numerator be=x

And the denominator be=x

According to the question, first Condition

Numerator is increased by 2 and

denominator is decreased by 1 fraction is

2/3

x+2/x-1-2/3

second condition,

The numerator is increased by 1 and

denominator is increased by 2 then

fraction becomes 1/3

First Condition

x+2/x-1-2/3

3tx+2-2x-1

3x+6-2x-2

3x-2x=-2-6

x=-8

Second Condition

x+2/x+1=1/3

3[x+2]-x+1

3x+6-x+1

3x-x=6-1

2x5

x=5/2

Step-by-step explanation:

Hope it helps you