Question

Can someone help me with this?

Answer 1

Step-by-step explanation:

5. The numbers are in the ratio 4:5:6

Then we can say that the three numbers may be 4a,5a,6a

Given: sum of largest and smallest = third + 55

therefore, 6a+4a=5a+55

10a=5a+55

10a-5a=55

5a=55

a=11

hence, the numbers are 4(11)=44

5(11)=55

6(11) =66

For verification:-

6a+4a=5a+55

66+55=55+55

110=110

Hope it helps✌✌