Math, asked by khushikanungo2pdxcn7, 1 year ago

can someone help me with this question??

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Answered by siddhartharao77
2

First number which when divided by 4 yields 1 as remainder is 13. [13/4 = 1].

Last number which when divided by 4 yields 1 as remainder 1 is 97.[97/4 = 1]

Hence, the AP is 13,17,21,25,...97

Now,

First term a = 13.

Common difference d = 17 - 13 = 4

Last term an = 97.


We know that an = a + (n - 1) * d

= > 97 = 13 + (n - 1) * 4

= > 97 - 13 = 4n - 4

= > 84 = 4n - 4

= > 88 = 4n

= > n = 22.


Now,

Sum of n terms of an AP sn = (n/2)[a + l]

⇒ 22/2[13 + 97]

⇒ 11[110]

⇒ 1210.


Therefore, the answer is 1210 - Option(B).


Hope this helps!


khushikanungo2pdxcn7: thank you soo much
nainabatra14: most wlcm my dear
siddhartharao77: Welcome!
nainabatra14: hm
khushikanungo2pdxcn7: its just the two digit no. being divided by four right? not the sum of the two digits in the no. itself?
nainabatra14: ok yrr
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