can someone help me with this question I am writing my exam
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Given that PQRS is a rhombus
∠PSR=∠PQR=54°
(opp. ∠S of a rhombus are equal)
⇒∠OSR= 1/2 ×∠PSR= 1/2 ×54°=27°
(SQ bisects ∠PSR)
Now in ΔOSR
∠ORS+∠ROS+∠OSR=180°
⇒∠ORS+27° +90° =180°
(Diagonals of a rhombus bisect each other at right ∠s)
⇒∠ORS=63°
⇒∠PRS=63°
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