Math, asked by tommy345, 2 days ago

can someone help me with this question I am writing my exam​

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Answered by rg448826
0

Answer:

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Answered by Jiya0071
0

Given that PQRS is a rhombus

∠PSR=∠PQR=54°

(opp. ∠S of a rhombus are equal)

⇒∠OSR= 1/2 ×∠PSR= 1/2 ×54°=27°

(SQ bisects ∠PSR)

Now in ΔOSR

∠ORS+∠ROS+∠OSR=180°

⇒∠ORS+27° +90° =180°

(Diagonals of a rhombus bisect each other at right ∠s)

⇒∠ORS=63°

⇒∠PRS=63°

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