Can someone please answer my question
Factorise:2√2x^3+3√3y^3
Answers
Answered by
0
2√2x^3+3√3y^3
x3 +y3=[x+y][x2-xy+y2] identity 7 or 8
[√2x+√3y][2x2 -√6xy+3y2]
ebenjohn114:
I did not understand the answer
Similar questions