Can someone please explain the solution to this question?
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Anonymous:
6√2
sista any difficulty in understanding.
thanks bro
but is is possible for you to send the steps as to how you reached to the final answer?
Fine.
Mate see your message box. I explained this concept there.
Answers
Answered by
4
★★Heya★★
Here only conservative forces are available so, by using conservation of mechanical energy. i,e
∆U + ∆T = 0
U2 + T2 = U1 + T1
U2 = mg× 1.65
T2 = 1/2 ( m × ( V2 )²
U1 = mg × ( 4 )
T1 = 1/2 ( m ) × ( 5 )²
Solve this we get
V2 = 6√2m/s.
☺️☺️☺️
Here only conservative forces are available so, by using conservation of mechanical energy. i,e
∆U + ∆T = 0
U2 + T2 = U1 + T1
U2 = mg× 1.65
T2 = 1/2 ( m × ( V2 )²
U1 = mg × ( 4 )
T1 = 1/2 ( m ) × ( 5 )²
Solve this we get
V2 = 6√2m/s.
☺️☺️☺️
thanks!
Answered by
1
Answer:
Explanation:yas
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