Question

can someone please help me for this?​

Answer 1

Given:-

• $\sf{Final\:Velocity= 0m/s}$

• $\sf{Acceleration = 6m/s²}$

• $\sf{Time taken = 2s.}$

To Find :-

• Initial Velocity of the Car.

Formulae used:-

• ${\huge{\boxed{\underline{\rm{ v = u + at}}}}}$

Where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time.

Now,

$\implies\sf{ v = u + at}$

$\implies\sf { 0 = u + (-6) ( 2)}$

$\implies\sf{ - u = -12}$

$\implies\sf{\cancel{-} u = \cancel{-} 12}$.

Hence, The Initial Velocity of the car is 12m/s.

SOME MORE EQUATION

• ${\huge{\boxed{\underline{\sf{ v^2 - u^2 = 2as}}}}}$

• ${\huge{\boxed{\underline{\sf{ S = ut + \dfrac{1}{2}\times{a}\times{(t)^2}}}}}}$.

Answer 2

Given:-

\sf{Final\:Velocity= 0m/s}FinalVelocity=0m/s

\sf{Acceleration = 6m/s²}Acceleration=6m/s²

\sf{Time taken = 2s.}Timetaken=2s.

To Find :-

Initial Velocity of the Car.

Formulae used:-

{\huge{\boxed{\underline{\rm{ v = u + at}}}}}

v=u+at

Where,

v = Final Velocity

u = Initial Velocity

a = Acceleration

t = Time.

Now,

\implies\sf{ v = u + at}⟹v=u+at

\implies\sf { 0 = u + (-6) ( 2)}⟹0=u+(−6)(2)

\implies\sf{ - u = -12}⟹−u=−12

\implies\sf{\cancel{-} u = \cancel{-} 12}⟹

−

u=

−

12 .

Hence, The Initial Velocity of the car is 12m/s.

SOME MORE EQUATION

{\huge{\boxed{\underline{\sf{ v^2 - u^2 = 2as}}}}}

v

2

−u

2

=2as

{\huge{\boxed{\underline{\sf{ S = ut + \dfrac{1}{2}\times{a}\times{(t)^2}}}}}}

S=ut+

2

1

×a×(t)

2

.