Question

Find the area of a rhombus whose diagonals are of lengths 12 cms and 7.3 cms.​

Answer 1

Solution:-

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$\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}$

$\Longrightarrow$ Here it is given in the question that the length of diagonals of a rhombus are 12 cm and 7.3 cm respectively. Now the question has asked us to to find out the area of the given rhombus. So, to find out the area of the rhombus we will apply the formula of area of rhombus when it's diagonals are given that is ½ × D₁ × D₂. The result which we will get after solving by applying the formula will be the area.

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ANSWER:-

⪼ The area of the rhombus is 43.8 cm².

GIVEN:-

➤ Length of 1st diagonal (D₁) = 12 cm

➤ Length of 2nd diagonal (D₂) = 7.3 cm

TO FIND:-

⟹ Here we have to find the area of the rhombus.

SOLVING STEP BY STEP:-

• To find the area of a rhombus when it's diagonals are given we have to apply the formula that is ½ × D₁ × D₂. By applying this formula we will get the answer.
• Here, D₁ is = 12 cm
• Here, D₂ is = 7.3 cm

We know that:-

$\underline{\boxed{ \sf \bigstar Area\:of\: rhombus= \dfrac{1}{2} \times D₁ \times D₂}}$

Where,

• D₁ is Diagonal 1
• D₂ is Diagonal 2

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• Finding the area of rhombus:-

$\to \sf{Area = \dfrac{1}{2} \times 12 \: cm \times 7.3 \: cm}$

$\to\sf{Area= \dfrac{1}{2} \times 87.6 \: cm^{2} }$

$\to\sf{Area= \dfrac{1 \times 87.6 \: cm^{2}}{2}}$

$\to\sf{Area= \dfrac{87.6 \: cm^{2}}{2}}$

$\to\sf{Area= \dfrac{ \not{87.6}\: cm^{2}}{ \not{2}}} = 43.8$

$\overline {\boxed{\sf Area = 43.8 \: cm^{2} }}$

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